Unit 28: Magnetic Fields

28.1 - Magnetic Fields and the Definition of B\vec B

What Produces a Magnetic Field?

Because an electric field is produced by an electric charge, we might reasonably expect that a magnetic field is produced by a magnetic charge. Although individual magnetic charges (called magnetic monopoles) are predicted by certain theories, their existence has not been confirmed. How then are magnetic fields produced? There are two ways.

Moving electronically charged particles, such as a current in a wire, can be used to make an electromagnet. The current produces a magnetic field which can be controlled by controlling the flow of current through the wire.

The other way to produce a magnetic field is by means of elementary particles such as electrons because the particles have an intrinsic magnetic field around them. The magnetic fields of the electrons in certain materials add together to give a net magnetic field around the material. These materials are known as permanent magnets.

The Definition of B\vec B

The magnetic field B\vec B is defined in terms of the magnetic force FB\vec F_B exerted on a moving electrically charged test particle.

In principle, we do this by firing a charged particle through the point at which B\vec B is to be defined, using various directions and speeds for the particle and determining the force that acts on the particle at that point. After many such trials we would find that when the particle’s velocity v\vec v is along a particular axis through the point, force FB\vec F_B is zero. For all other directions of v\vec v, the magnitude of FB\vec F_B is always proportional to vsinϕv \sin \phi, where ϕ\phi is the angle between the zero-force axis and the direction of v\vec v.

We can then define a magnetic field B\vec B to be a vector quantity that is directed along the zero-force axis. We can next measure the magnitude of FB\vec F_B when v\vec v is directed perpendicular to that axis and then define the magnitude of B\vec B in terms of that force magnitude:

B=FbqvB = \frac{F_b}{|q|v}

where qq is the charge of the particle.

Finding the Magnetic Force on a Particle

The force FB\vec F_B on a particle from a magnetic field can be represented as a cross product:

FB=qv×B\vec F_B = q\vec v \times \vec B

that is, the force FB\vec F_B on the particle is equal to the charge qq times the cross product of its velocity v\vec v and the field B\vec B.

Thus, we can write the magnitude of FB\vec F_B as:

FB=qvBsinϕF_B = |q|vB \sin \phi

where ϕ\phi is the angle between the directions of the velocity v\vec v and the magnetic field B\vec B.

28.2 - Crossed Fields: Discovery of the Electron

If a charged particle moves through a region containing both an electric field and a magnetic field, it can be affected by both an electric force and a magnetic force.

If the fields are perpendicular to each other, they are said to be crossed fields.

If the forces are in opposite directions, a particular speed will result in no deflection of the particle.

28.3 - Crossed Fields: The Hall Effect

When a uniform magnetic field BB is applied to a conducting strip carrying current ii, with the field perpendicular to the direction of the current, a Hall-effect potential difference VV is set up across the strip.

The electric force FE\vec F_E on the charge carriers is then balanced by the magnetic force FB\vec F_B on them.

The number density n of the charge carriers can then be determined from:

n=BiVlen = \frac{Bi}{Vle}

where ll is the thickness of the strip (parallel to B\vec B).

When a conductor moves through a uniform magnetic field B\vec B at speed vv, the Hall-effect potential difference VV across it is:

V=vBdV = vBd

where dd is the width perpendicular to both velocity v\vec v and field B\vec B.

28.4 - A Circulating Charged Particle

A charged particle with mass mm and charge magnitude q|q| moving with velocity v\vec v perpendicular to a uniform magnetic field B\vec B will travel in a circle.

Applying Newton’s second law to the circular motion yields:

qvB=mv2r|q|vB = \frac{mv^2}{r}

from which we find the radius rr of the circle to be

r=mvqBr = \frac{mv}{|q|B}

The frequency of revolution ff, the angular frequency ω\omega, and the period of the motion TT are given by:

f=ω2π=1T=qB2πmf = \frac{\omega}{2\pi} = \frac{1}{T} = \frac{|q|B}{2\pi \cdot m}

If the velocity of the particle has a component parallel to the magnetic field, the particle moves in a helical path around the field vector B\vec B.

28.5 - Cyclotrons and Synchrotrons

A cyclotron is a form of particle accelerator in which particles are made to circulate using an an electrical oscillator to induce magnetic fields that slowly increase the speed of the particles (e.g. protons).

Frequency

The key to the operation of the cyclotron is that the frequency ff at which the proton circulates in the magnetic field (and that does not depend on its speed) must be equal to the fixed frequency foscf_{osc} of the electrical oscillator:

f=fosc(resonance condition)f = f_{osc} \hspace{1.5em} \textrm{(resonance condition)}

which can be used in combination with the above equation for frequency to obtain:

qB=2πmfosc|q|B = 2\pi m f_{osc}

The Proton Synchrotron

At proton energies above 50 MeV, the conventional cyclotron begins to fail because one of the assumptions of its design—that the frequency of revolution of a charged particle circulating in a magnetic field is independent of the particle’s speed—is true only for speeds that are much less than the speed of light.

The proton synchrotron corrects for the relativity and feasibility problems of a traditional cyclotron. The magnetic field BB and the oscillator frequency foscf_{osc}, instead of having field values as in the conventional cyclotron, are made to vary with time during accelerating cycle.

28.6 - Magnetic Force on a Current-Carrying Wire

A straight wire carrying a current ii in a uniform magnetic field experiences a sideways force:

FB=iL×B\vec F_B = i\vec L \times \vec B

The force acting on a current element i dLi \space d\vec L in a magnetic field is:

dFB=i dL×Bd \vec F_B = i \space d\vec L \times \vec B

The direction of the length vector L\vec L or dLd\vec L is that of the current ii.

28.7 - Torque on a Current Loop

Various magnetic forces act on the sections of a current-carrying coil lying in a uniform external magnetic field, but the net force is zero.

The net torque acting on the coil has a magnitude given by:

τ=NiABsinθ\tau = NiAB \sin \theta

where NN is the number of turns in the coil, AA is the area of each turn, ii is the current, BB is the field magnitude, and θ\theta is the angle between the magnetic field B\vec B and the normal vector to the coil n\vec n.

28.8 - The Magnetic Dipole Moment

A coil (of area AA and NN turns, carrying current ii) in a uniform magnetic field will experience a torque given by:

τ=μ×B\vec \tau = \vec \mu \times \vec B

Here μ\vec \mu is the magnetic dipole moment of the coil, with magnitude μ=NiA\mu = NiA and direction given by the right-hand rule.

The orientation energy of a magnetic dipole in a magnetic field is given by:

U(θ)=μBU(\theta) = -\vec \mu \cdot \vec B

If an external agent rotates a magnetic dipole from an initial orientation θi\theta_i to some other orientation θf\theta_f and the dipole is stationary both initially and finally, the work WaW_a done on the dipole by the agent is:

Wa=ΔU=UfUiW_a = \Delta U = U_f - U_i